1
MHT CET 2024 3rd May Morning Shift
MCQ (Single Correct Answer)
+2
-0

If $|z|=1$ and $w=\frac{z-1}{z+1}$ (where $\left.z \neq-1\right)$, then $\operatorname{Re}(w)$ is

A
0
B
$-\frac{1}{|z+1|^2}$
C
$\left|\frac{z}{z+1}\right| \cdot \frac{1}{|z+1|^2}$
D
$\frac{\sqrt{2}}{|z+1|^2}$
2
MHT CET 2024 3rd May Morning Shift
MCQ (Single Correct Answer)
+2
-0

If $g(x)=x^2+x-1$ and (gof) $(x)=4 x^2-10 x+5$, then $\mathrm{f}(2)$ is equal to

A
1
B
$-$1
C
2
D
$-$2
3
MHT CET 2024 3rd May Morning Shift
MCQ (Single Correct Answer)
+2
-0

The shaded area in the figure below is the solution set for a certain linear programming problem, then the linear constraints are given by

MHT CET 2024 3rd May Morning Shift Mathematics - Linear Programming Question 19 English

A
$x \geqslant 1, y \leqslant 3, x-2 y \geqslant 2,6 x+7 y \leqslant 42, x \geqslant 0, y \geqslant 0$
B
$x \geqslant 1, y \leqslant 3, x-2 y \geqslant 2,6 x+7 y \geqslant 42, x \geqslant 0, y \geqslant 0$
C
$x \leqslant 1, y \geqslant 3, x-2 y \leqslant 2,6 x+7 y \leqslant 42, x \geqslant 0, y \geqslant 0$
D
$x \geqslant 1, y \leqslant 3, x-2 y \leqslant 2,6 x+7 y \leqslant 42, x \geqslant 0, y \geqslant 0$
4
MHT CET 2024 3rd May Morning Shift
MCQ (Single Correct Answer)
+2
-0

The equation of the normal to the curve $x=\theta+\sin \theta, y=1+\cos \theta$ at $\theta=\frac{\pi}{2}$ is

A
$2 x+2 y+\pi=0$
B
$2 x-2 y-\pi=0$
C
$x+y+\pi=0$
D
$x+y-2 \pi=0$
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