1
MHT CET 2024 2nd May Evening Shift
MCQ (Single Correct Answer)
+1
-0

The displacement of a particle performing S.H.M. is given by $Y=A \cos [\pi(t+\phi)]$. If at $\mathrm{t}=0$, the displacement is $\mathrm{y}=2 \mathrm{~cm}$ and velocity is $2 \pi \mathrm{~cm} / \mathrm{s}$, the value of amplitude $A$ in cm is

A
2
B
$\sqrt{2}$
C
$2 \sqrt{2}$
D
$\frac{1}{\sqrt{2}}$
2
MHT CET 2024 2nd May Evening Shift
MCQ (Single Correct Answer)
+1
-0

The string of pendulum of length ' $L$ ' is displaced through $90^{\circ}$ from the vertical and released. Then the maximum strength of the string in order to withstand the tension, as the pendulum passes through the mean position is ( $\mathrm{m}=$ mass of pendulum, $\mathrm{g}=$ acceleration due to gravity)

A
mg
B
3 mg
C
5 mg
D
6 mg
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