1
MHT CET 2024 2nd May Evening Shift
MCQ (Single Correct Answer)
+2
-0

Let $X=\left[\begin{array}{l}\mathrm{a} \\ \mathrm{b} \\ \mathrm{c}\end{array}\right], \mathrm{A}=\left[\begin{array}{ccc}1 & -1 & 2 \\ 2 & 0 & 1 \\ 3 & 2 & 1\end{array}\right]$ and $\mathrm{B}=\left[\begin{array}{l}3 \\ 1 \\ 4\end{array}\right]$. If $A X=B$, then the value of $2 a-3 b+4 c$ will be

A
0
B
$-$4
C
6
D
4
2
MHT CET 2024 2nd May Evening Shift
MCQ (Single Correct Answer)
+2
-0

Let in a Binomial distribution, consisting of 5 independent trials, probabilities of exactly 1 and 2 successes be 0.4096 and 0.2048 respectively. Then the probability of getting exactly 3 successes is equal to

A
$\frac{80}{243}$
B
$\frac{40}{7243}$
C
$\frac{32}{625}$
D
$\frac{128}{625}$
3
MHT CET 2024 2nd May Evening Shift
MCQ (Single Correct Answer)
+2
-0

The unit vector which is orthogonal to the vector $5 \hat{i}+2 \hat{j}+6 \hat{k}$ and is coplanar with the vectors $2 \hat{i}+\hat{j}+\hat{k}$ and $\hat{i}-\hat{j}+\hat{k}$ is

A
$\frac{2 \hat{i}-6 \hat{j}+\hat{k}}{\sqrt{41}}$
B
$\frac{2 \hat{i}-5 \hat{j}}{\sqrt{29}}$
C
$\frac{-3 \hat{\mathrm{j}}+\hat{\mathrm{k}}}{\sqrt{10}}$
D
$\frac{2 \hat{\mathrm{i}}-8 \hat{\mathrm{j}}+\hat{\mathrm{k}}}{69}$
4
MHT CET 2024 2nd May Evening Shift
MCQ (Single Correct Answer)
+2
-0

The probability distribution of a random variable X is given by

$\mathrm{X=}x_i$: 0 1 2 3 4
$\mathrm{P(X=}x_i)$ : 0.4 0.3 0.1 0.1 0.1

Then the variance of X is

A
1.76
B
2.45
C
3.2
D
4.8
MHT CET Papers
EXAM MAP
Medical
NEETAIIMS
Graduate Aptitude Test in Engineering
GATE CSEGATE ECEGATE EEGATE MEGATE CEGATE PIGATE IN
Civil Services
UPSC Civil Service
Defence
NDA
Staff Selection Commission
SSC CGL Tier I
CBSE
Class 12