1
MHT CET 2024 2nd May Evening Shift
MCQ (Single Correct Answer)
+2
-0

$\tan \left(\frac{\pi}{4}+\frac{1}{2} \cos ^{-1}\left(\frac{\mathrm{a}}{\mathrm{b}}\right)\right)+\tan \left(\frac{\pi}{4}-\frac{1}{2} \cos ^{-1}\left(\frac{\mathrm{a}}{\mathrm{b}}\right)\right)$ is

A
$\frac{2 a}{b}$
B
$\frac{2 \mathrm{~b}}{\mathrm{a}}$
C
$\frac{\mathrm{a}}{\mathrm{b}}$
D
$\frac{\mathrm{b}}{\mathrm{a}}$
2
MHT CET 2024 2nd May Evening Shift
MCQ (Single Correct Answer)
+2
-0

Consider three observations $\mathrm{a}, \mathrm{b}$ and c such that $b=a+c$. If the standard deviation of $\mathrm{a}+2, \mathrm{~b}+2, \mathrm{c}+2$ is d , then ............ holds.

A
$\mathrm{b}^2=3\left(\mathrm{a}^2+\mathrm{c}^2+\mathrm{d}^2\right)$
B
$\mathrm{b}^2=\mathrm{a}^2+\mathrm{c}^2+3 \mathrm{~d}^2$
C
$b^2=3\left(a^2+c^2\right)-9 d^2$
D
$\mathrm{b}^2=3\left(\mathrm{a}^2+\mathrm{c}^2\right)+9 \mathrm{~d}^2$
3
MHT CET 2024 2nd May Evening Shift
MCQ (Single Correct Answer)
+2
-0

The area (in sq. units) bounded by the curves $y=\sqrt{x}, 2 y-x+3=0, X$-axis and lying in the first quadrant is

A
36
B
18
C
$\frac{27}{4}$
D
9
4
MHT CET 2024 2nd May Evening Shift
MCQ (Single Correct Answer)
+2
-0

If the lengths of the sides of triangle are 3,5,7, then the largest angle of the triangle is

A
$\frac{\pi}{2}$
B
$\frac{5 \pi}{6}$
C
$\frac{2 \pi}{3}$
D
$\frac{3 \pi}{4}$
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