1
GATE EE 2010
+2
-0.6
A three-phase, $$33$$ kV oil circuit breaker is rated $$1200$$ A, $$2000$$ MVA, $$3$$s. The symmetrical breaking current is
A
$$1200$$ A
B
$$3600$$ A
C
$$35$$ kA
D
$$104.8$$ kA
2
GATE EE 2010
+2
-0.6
Consider a stator winding of an alternator with an internal high resistance ground fault. The currents under the fault condition are as shown in the figure. The winding is protected using a differential current scheme with current transformers of ratio $$400/5$$ $$A$$ as shown. The current through the operating coil is
A
$$0.1875$$ $$A$$
B
$$0.2$$ $$A$$
C
$$0.375$$ $$A$$
D
$$60$$ $$kA$$
3
GATE EE 2010
+1
-0.3
Power is transferred from system $$A$$ to system $$B$$ by an $$HVDC$$ link as shown in the figure. If the voltage $${V_{AB}}$$ and $${V_{CD}}$$ are as indicated in the figure, and 1 > 0, then
A
$${V_{AB}}\, < \,0,\,\,{V_{CD}}\, < 0,\,\,{V_{AB}}\, > \,{V_{CD}}$$
B
$${V_{AB}}\, > \,0,\,\,{V_{CD}}\, > 0,\,\,{V_{AB}}\, < \,{V_{CD}}$$
C
$${V_{AB}}\, > \,0,\,\,{V_{CD}}\, > 0,\,\,{V_{AB}}\, > \,{V_{CD}}$$
D
$${V_{AB}}\, > \,0,\,\,{V_{CD}}\, < 0,\,\,{V_{AB}}\, > \,{V_{CD}}$$
4
GATE EE 2010
+2
-0.6
For the power system shown in the figure below, the specifications of the components are the following:
$$G1: 25$$ $$kV,$$ $$100$$ $$MVA,$$ $$X=9$$%
$$G2: 25$$ $$kV,$$ $$100$$ $$MVA,$$ $$X=9$$%
$$T1: 25$$ $$kV/220$$ $$kV,$$ $$90$$ $$MVA,$$ $$X=12$$%
$$T2: 220$$ $$kV/ 25$$ $$kV,$$ $$90$$ $$MVA,$$ $$X=12$$%
$$Line$$ $$1: 220$$ $$kV,$$ $$X= 150$$ $$ohms$$

Choose $$25$$ $$kV$$ as the base voltage at the generator $$G1,$$ and $$200$$ $$MVA$$ as the $$MVA$$ base. The impedance diagram is

A
B
C
D
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