1
GATE EE 2010
MCQ (Single Correct Answer)
+1
-0.3
The period of the signal $$x\left(t\right)=8\sin\left(0.8\mathrm{πt}+\frac{\mathrm\pi}4\right)$$ is
A
$$0.4\;\mathrm\pi\;\mathrm s$$
B
$$0.8\;\mathrm\pi\;\mathrm s$$
C
1.25 s
D
2.5 s
2
GATE EE 2010
MCQ (Single Correct Answer)
+2
-0.6
x(t) is a positive rectangular pulse from t = -1 to t = +1 with unit height as shown in the figure. The value of $$\int_{-\infty}^\infty\left|X\left(\omega\right)\right|^2d\omega$$ {where X($$\mathrm\omega$$) is the Fourier transform of x(t)} is GATE EE 2010 Signals and Systems - Continuous Time Signal Fourier Transform Question 2 English
A
2
B
2$$\mathrm\pi$$
C
4
D
4$$\mathrm\pi$$
3
GATE EE 2010
MCQ (Single Correct Answer)
+2
-0.6
Given f(t) and g(t)as shown below: GATE EE 2010 Signals and Systems - Miscellaneous Question 1 English The Laplace transform of g(t) is
A
$$\frac1s\left(e^{3s}\;-\;e^{5s}\right)$$
B
$$\frac1s\left(e^{-5s}\;-\;e^{-3s}\right)$$
C
$$\frac{e^{-3s}}s\left(1\;-\;e^{-2s}\right)$$
D
$$\frac1s\left(e^{5s}\;-\;e^{3s}\right)$$
4
GATE EE 2010
MCQ (Single Correct Answer)
+2
-0.6
Given f(t) and g(t)as shown below: GATE EE 2010 Signals and Systems - Miscellaneous Question 2 English g(t) can be expressed as
A
g(t) = f(2t - 3)
B
g(t) = $$f\left(\frac t2-3\right)$$
C
g(t) = $$f\left(2t-\frac32\right)$$
D
g(t) = $$f\left(\frac t2-\frac32\right)$$
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