GATE EE 2010 | GATE EE Year Wise Previous Years Questions

GATE EE 2010

MCQ (Single Correct Answer)

-0.3

The switch in the circuit has been closed for a long time. It is opened at t = 0. At t = 0⁺, the current through the 1μF capacitor is GATE EE 2010 Electric Circuits - Transient Response Question 30 English

GATE EE 2010 Electric Circuits - Transient Response Question 30 English

0 A

1 A

1.25 A

5 A

GATE EE 2010

MCQ (Single Correct Answer)

-0.6

The two-port network P shown in the figure has ports 1 and 2, denoted by terminals (a, b) and (c, d), respectively. It has an impedance matrix Z with parameters denoted by z_ij. A 1 Ω resistor is connected in series with the network at port 1 as shown in the figure. The impedance matrix of the modified two-port network (shown as a dashed box) is GATE EE 2010 Electric Circuits - Two Port Networks Question 11 English

GATE EE 2010 Electric Circuits - Two Port Networks Question 11 English

$$\begin{pmatrix}z_{11}+1&z_{12}+1\\z_{21}&z_{22}+1\end{pmatrix}$$

$$\begin{pmatrix}z_{11}+1&z_{12}\\z_{21}&z_{22}+1\end{pmatrix}$$

$$\begin{pmatrix}z_{11}+1&z_{12}\\z_{21}&z_{22}\end{pmatrix}$$

$$\begin{pmatrix}z_{11}+1&z_{12}\\z_{21}+1&z_{22}\end{pmatrix}$$

GATE EE 2010

MCQ (Single Correct Answer)

-0.3

As shown in the figure, a 1 Ω resistance is connected across a source that has a load line v + i = 100. The current through the resistance is GATE EE 2010 Electric Circuits - Network Elements Question 47 English

GATE EE 2010 Electric Circuits - Network Elements Question 47 English

25 A

50 A

100 A

200 A

GATE EE 2010

MCQ (Single Correct Answer)

-0.3

An ammeter has a current range of $$0$$-$$5A,$$ and its internal resistance is $$0.2\Omega $$. In order to change the range to $$0$$-$$25$$ $$A$$ we need to add a resistance of

$$0.8\,\Omega $$ in series with the meter

$$1.0\,\Omega $$ in series with the meter.

$$0.04\,\Omega $$ in parallel with the meter

$$0.05\,\Omega $$ in parallel with the meter

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