WB JEE 2017 | Dual Nature of Radiation Question 6 | Physics

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MCQ (Single Correct Answer)

+1

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When light of frequency v₁ is incident on a metal with work function W (where hv₁ > W), then photocurrent falls to zero at a stopping potential of V₁. If the frequency of light is increased to v₂, the stopping potential changes to V₂. Therefore, the charge of an electron is given by

A

$${{W({v_2} + {v_1})} \over {{v_1}{V_2} + {v_2}{V_1}}}$$

B

$${{W({v_2} + {v_1})} \over {{v_1}{V_1} + {v_2}{V_2}}}$$

C

$${{W({v_2} - {v_1})} \over {{v_1}{V_2} - {v_2}{V_1}}}$$

D

$${{W({v_2} - {v_1})} \over {{v_2}{V_2} - {v_1}{V_1}}}$$