WB JEE 2026 | Alternating Current Question 1 | Physics

WB JEE 2026

MCQ (Single Correct Answer)

-0.25

A resistor of resistance＇$R$＇draws power＇$P$＇when connected to an AC source．If an inductance is now placed in series with $R$ ，such that the impedance of the circuit becomes＇$Z$＇，the power drawn will be

$P\left(\frac{R}{Z}\right)$

$P\left(\frac{R}{Z}\right)^3$

$P\left(\frac{R}{Z}\right)^2$

$P \sqrt{\frac{Z}{R}}$

WB JEE 2025

MCQ (Single Correct Answer)

-0.25

For a domestic AC supply of 220 V at 50 cycles per sec, the potential difference between the terminals of a two-pin electric outlet in a room is given by

$\mathrm{V}(\mathrm{t})=220 \sqrt{2} \operatorname{Cos}(100 \pi \mathrm{t})$

$V(t)=220 \operatorname{Sin}(50 t)$

$\mathrm{V}(\mathrm{t})=220 \operatorname{Cos}(100 \pi \mathrm{t})$

$\mathrm{V}(\mathrm{t})=220 \sqrt{2} \operatorname{Cos}(50 \mathrm{t})$

WB JEE 2024

MCQ (Single Correct Answer)

-0.25

WB JEE 2024 Physics - Alternating Current Question 4 English

In a series LCR circuit, the rms voltage across the resistor and the capacitor are $$30 \mathrm{~V}$$ and $$90 \mathrm{~V}$$ respectively. If the applied voltage is $$50 \sqrt{2} \sin \omega t$$, then the peak voltage across the inductor is

70 V

50 V

70$$\sqrt2$$ V

50$$\sqrt2$$ V

WB JEE 2022

MCQ (Single Correct Answer)

-0.25

When an AC source of emf E with frequency $$\omega$$ = 100 Hz is connected across a circuit, the phase difference between E and current I in the circuit is observed to be $${\pi \over 4}$$ as shown in the figure. If the circuit consist of only RC or RL in series, then

WB JEE 2022 Physics - Alternating Current Question 4 English

R = 1 k$$\Omega$$, C = 5 $$\mu$$F

R = 1 k$$\Omega$$, L = 10 H

R = 1 k$$\Omega$$, L = 1 H

R = 1 k$$\Omega$$, C = 10 $$\mu$$F

WB JEE Subjects

Browse all chapters by subject