1
WB JEE 2024
MCQ (Single Correct Answer)
+1
-0.25
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A beam of light of wavelength $$\lambda$$ falls on a metal having work function $$\phi$$ placed in a magnetic field B. The most energetic electrons, perpendicular to the field are bent in circular arcs of radius R. If the experiment is performed for different values of $$\lambda$$, then $$\mathrm{B}^2$$ vs. $$\frac{1}{\lambda}$$ graph will look like (keeping all other quantities constant)

A
WB JEE 2024 Physics - Dual Nature of Radiation Question 1 English Option 1
B
WB JEE 2024 Physics - Dual Nature of Radiation Question 1 English Option 2
C
WB JEE 2024 Physics - Dual Nature of Radiation Question 1 English Option 3
D
WB JEE 2024 Physics - Dual Nature of Radiation Question 1 English Option 4
2
WB JEE 2017
MCQ (Single Correct Answer)
+1
-0.25
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When light of frequency v1 is incident on a metal with work function W (where hv1 > W), then photocurrent falls to zero at a stopping potential of V1. If the frequency of light is increased to v2, the stopping potential changes to V2. Therefore, the charge of an electron is given by
A
$${{W({v_2} + {v_1})} \over {{v_1}{V_2} + {v_2}{V_1}}}$$
B
$${{W({v_2} + {v_1})} \over {{v_1}{V_1} + {v_2}{V_2}}}$$
C
$${{W({v_2} - {v_1})} \over {{v_1}{V_2} - {v_2}{V_1}}}$$
D
$${{W({v_2} - {v_1})} \over {{v_2}{V_2} - {v_1}{V_1}}}$$
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