1
TS EAMCET 2023 (Online) 13th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

When the origin is shifted to the point $(h, k)$ by translating the coordinates axes, the equation $S \equiv 2 x^2-x y+y^2+2 x+3 y+1=0$ is changed to $S \equiv a x^2+2 h x y+b y^2-3=0$. Again by rotating the coordinate axes about the new origin through the angle $\theta$ in the positive direction, $S^{\prime}=0$ is changed to $A x^2+B y^2+C=0$. Then, $h+k+\tan 2 \theta=$

A

-4

B

0

C

1

D

-1

2
TS EAMCET 2023 (Online) 13th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

In an ellipse, the distance from one of the foci to its corresponding end of the major axis is $4-\sqrt{7}$ and the distance from same focus to one end of the minor axis is 4 . Then, the cosine of the angle subtended by the line segment joining its foci at one end of its minor axis is

A

$\frac{1}{8}$

B

$\frac{3}{4}$

C

$\frac{\sqrt{7}}{3}$

D

$\frac{1}{3 \sqrt{7}}$

3
TS EAMCET 2023 (Online) 13th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

If the equations $x=1+2 \cos \theta, y=2+\sin \theta, 0 \leq \theta<2 \pi$ represent an ellipse, then the point of intersection of the normal drawn at $P\left(\frac{\pi}{4}\right)$ to this ellipse and its major axis is

A

$\left(\frac{4-\sqrt{3}}{4}, 0\right)$

B

$\left(\frac{\sqrt{3}+1}{4}, 0\right)$

C

$\left(\frac{8+\sqrt{3}}{2}, 0\right)$

D

$\left(\frac{5}{2}, 0\right)$

4
TS EAMCET 2023 (Online) 13th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

Let $A=(2,0)$ and $B=(0,-2)$. Let $P$ be any point such that the sum of the distance of $P$ from $A$ and $B$ is 4 . Then, the equation of the locus of the point $P$ is

A

$3 x^2-2 x y+3 y^2-4 x+12 y+16=0$

B

$3 x^2-2 x y+3 y^2-8 x+8 y=0$

C

$3 x^2+2 x y+3 y^2+8 x-8 y=0$

D

$3 x^2+2 x y+3 y^2+4 x-12 y+16=0$

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