1
TG EAPCET 2025 (Online) 3rd May Evening Shift
MCQ (Single Correct Answer)
+1
-0

If the perpendicular distance from the focus of an ellipse $\frac{x^2}{9}+\frac{y^2}{b^2}=1(b<3)$ to its corresponding directrix is $\frac{4}{\sqrt{5}}$, then the slope of the tangent to this ellipse drawn at $\left(\frac{3}{\sqrt{2}}, \frac{b}{\sqrt{2}}\right)$ is

A

$-\frac{2}{3}$

B

$\frac{2}{3}$

C

$\frac{3}{2}$

D

$-\frac{3}{2}$

2
TG EAPCET 2025 (Online) 3rd May Evening Shift
MCQ (Single Correct Answer)
+1
-0

The length of the chord of the ellipse $\frac{x^2}{4}+y^2=1$ formed on the line $y=x+1$ is

A

$2 \sqrt{2}$

B

$\frac{4}{5} \sqrt{2}$

C

$4 \sqrt{2}$

D

$\frac{8}{5} \sqrt{2}$

3
TG EAPCET 2025 (Online) 3rd May Morning Shift
MCQ (Single Correct Answer)
+1
-0

Let $P$ be a point on the ellipse $\frac{x^2}{9}+\frac{y^2}{4}=1$ and let the perpendicular drawn through $P$ to the major axis meet its auxiliary circle at $Q$. If the normals drawn at $P$ and $Q$ to the ellipse and the auxiliary circle respectively meet in $R$, then the equation of the locus of $R$ is

A

$x^2+y^2=5$

B

$x^2+y^2=13$

C

$x^2+y^2=25$

D

$x^2+y^2=1$

4
TG EAPCET 2025 (Online) 3rd May Morning Shift
MCQ (Single Correct Answer)
+1
-0

The mid-point of the chord of the ellipse $x^2+\frac{y^2}{4}=1$ formed on the line $y=x+1$ is

A

$\left(\frac{4}{5}, \frac{9}{5}\right)$

B

$\left(-\frac{1}{5}, \frac{4}{5}\right)$

C

$\left(\frac{1}{5}, \frac{6}{5}\right)$

D

$\left(-\frac{6}{5},-\frac{1}{5}\right)$

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