1
TS EAMCET 2023 (Online) 13th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

Let $P$ be the point to which origin has to be shifted by the translation of axes, so as to remove the first degree terms from the equation $3 x^2+y^2-6 x+4 y+4=0$. If the origin is shifted to $P$ by the translation of axes, then the transformed equation of $2 x^2+3 x y-5 y^2+2 x-23 y-24=0$ is

A

$x^2+4 x y-3 y^2-4 x+20 y+23=0$

B

$2 x^2-3 x y+5 y^2=0$

C

$2 x^2+3 x y-5 y^2=0$

D

$2 x^2+3 x y-5 y^2-13=0$

2
TS EAMCET 2023 (Online) 13th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

Let $S$ and $S^{\prime}$ be the foci of an ellipse $E$ and $B$ be one end of its minor axis. Let $\angle S^{\prime} S B=\pi / 6$ and $(2 \sqrt{3}, 1)$ be a point on $E$. If $X$-axis is the major axis and $Y$-axis is the minor axis of the ellipse $E$, then the sum of the squares of the lengths of major and minor axis is

A

20

B

60

C

80

D

100

3
TS EAMCET 2023 (Online) 13th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

If $4 x+2 y+n=0$ is a normal to the ellipse $\frac{x^2}{36}+\frac{y^2}{16}=1$ then $n=$

A

$\pm \frac{9}{4}$

B

$\pm \frac{9}{\sqrt{10}}$

C

$\pm \frac{5}{4}$

D

$\pm 8$

4
TS EAMCET 2023 (Online) 12th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

The locus of the mid-points of the intercepted portion of the tangents by the coordinate axes, which are drawn to the ellipse $x^2+2 y^2=2$ is

A
$\frac{1}{2 x^2}+\frac{1}{4 y^2}=1$
B
$\frac{1}{4 x^2}+\frac{1}{2 y^2}=1$
C
$\frac{x^2}{2}+\frac{y^2}{4}=1$
D
$\frac{x^2}{4}+\frac{y^2}{2}=1$

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