1
AP EAPCET 2022 - 4th July Morning Shift
+1
-0

Two positive point charges of $$10 \mu \mathrm{C}$$ and $$12 \mu \mathrm{C}$$ are placed 10 cm apart in air. The work done to bring them 6 cm closer is

A
8.1 J
B
3.2 J
C
9 J
D
13.5 J
2
AP EAPCET 2021 - 20th August Morning Shift
+1
-0

What is the electric flux for Gaussian surface $$A$$ that encloses the charged particles in free space? [Given, $$q_1=-14 \mathrm{~nC}, q_2=78.85 \mathrm{~nC}, \left.q_3=-56 \mathrm{~nC}\right]$$

A
$$10^3 \mathrm{~N}-\mathrm{m}^2 \mathrm{C}^{-1}$$
B
$$10^3 \mathrm{C}-\mathrm{N}^{-1} \mathrm{~m}^{-2}$$
C
$$632 \times 10^3 \mathrm{~N}-\mathrm{m}^2 \mathrm{C}^{-1}$$
D
$$632 \times 10^3 \mathrm{C}-\mathrm{N}^{-1} \mathrm{~m}^{-2}$$
3
AP EAPCET 2021 - 20th August Morning Shift
+1
-0

Two charges 8 $$\mu$$C each are placed at the corners A and B of an equilateral triangle of side 0.2 m in air. The electric potential at the third corner C is

A
7.2 $$\times$$ 10$$^5$$ V
B
1.8 $$\times$$ 10$$^5$$ V
C
3.6 $$\times$$ 10$$^5$$ V
D
3.6 $$\times$$ 10$$^4$$ V
4
AP EAPCET 2021 - 19th August Evening Shift
+1
-0

Gauss's law helps in

A
determination of electric force between point charges
B
situation where Coulomb's law fails
C
determination of electric field due to symmetric charge distributions
D
determining electric potential due to symmetric charge distributions
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