1
TS EAMCET 2022 (Online) 20th July Evening Shift
MCQ (Single Correct Answer)
+1
-0

Numerically greatest term in the expansion of $(2 x-3 y)^{11}$ when $x=\frac{1}{3}$ and $y=\frac{1}{2}$ is

A

${ }^{11} C_8\left(\frac{2}{3}\right)^5$

B

${ }^{11} C_3\left(\frac{3}{2}\right)^5$

C

${ }^{11} C_2\left(\frac{3}{2}\right)^7$

D

${ }^{11} C_2\left(\frac{2}{3}\right)^7$

2
TS EAMCET 2022 (Online) 20th July Morning Shift
MCQ (Single Correct Answer)
+1
-0

$\frac{1}{8}-\frac{7}{8 \cdot 12}+\frac{7 \cdot 10}{8 \cdot 12 \cdot 16}-\ldots=$

A

$\sqrt[3]{\frac{4}{7}}$

B

$\sqrt[3]{\frac{4}{7}}-\frac{3}{4}$

C

$\sqrt[3]{\frac{4}{7}}+\frac{3}{4}$

D

$\sqrt[3]{\frac{7}{4}}-\frac{3}{4}$

3
TS EAMCET 2022 (Online) 19th July Evening Shift
MCQ (Single Correct Answer)
+1
-0

The expansion of $(a+x)^n$ contains 15 terms. When $x=1$ the ratio of the neighbouring terms to the middle term in this expansion is 16 . Then, the positive integral value of ' $a$ ' is

A

1

B

3

C

4

D

2

4
TS EAMCET 2022 (Online) 19th July Morning Shift
MCQ (Single Correct Answer)
+1
-0

If $k$ is the coefficient of $x^5$ in the expansion of $\left(2 x^2-\frac{1}{3 x^3}\right)^5$, then $\frac{3 k}{2}=$

A

-20

B

-40

C

20

D

40

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