1
TS EAMCET 2023 (Online) 13th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

If $|x|$ is so small that $x^3$ and higher powers of $x$ can be neglected, then an approximate value of $\frac{1}{\sqrt{4-x}(2+x)^3}$ is

A

$\frac{1}{16}\left(1+\frac{13 x}{8}+\frac{219}{128} x^2\right)$

B

$\frac{1}{8}\left(1+\frac{11 x}{8}-\frac{165}{128} x^2\right)$

C

$\frac{1}{32}\left(1-\frac{11 x}{8}+\frac{219}{128} x^2\right)$

D

$\frac{1}{16}\left(1-\frac{11 x}{8}+\frac{171}{128} x^2\right)$

2
TS EAMCET 2023 (Online) 12th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

The number of integral terms in the expansion of $(\sqrt{3}+\sqrt[8]{5})^{256}$ is

A
32
B
33
C
34
D
35
3
TS EAMCET 2023 (Online) 12th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

The expansion of $\left(1+x+x^2\right)^{-3 / 2}$ in powers of $x$ is valid, if

A
$|x|<1$
B
$|x|<\frac{1}{2}$
C
$\left|x+\frac{1}{2}\right|<\frac{\sqrt{5}}{2}$
D

$-\frac{1}{2}-\frac{\sqrt{5}}{2} < x < 1$

4
TS EAMCET 2023 (Online) 12th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

If $(1+x)^n=c_0+c_1 x+c_2 x^2+\ldots \ldots+c_n x^n$ for $n \in N$, then $c_0+\frac{c_1}{2}+\frac{c_2}{3}+\ldots \ldots+\frac{c_n}{n+1}=$

A
$\frac{2^n-1}{n+1}$
B
$\frac{2^n-1}{n}$
C
$\frac{2^{n+1}-1}{n+1}$
D
$\frac{2^{n+1}-1}{n}$

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