1
WB JEE 2017
MCQ (Single Correct Answer)
+1
-0.25
Change Language
Let P be the foot of the perpendicular from focus S of hyperbola $${{{x^2}} \over {{a^2}}} - {{{y^2}} \over {{b^2}}} = 1$$ on the line bx $$-$$ ay = 0 and let C be the centre of the hyperbola. Then, the area of the rectangle whose sides are equal to that of SP and CP is
A
2ab
B
ab
C
$${{({a^2} + {b^2})} \over 2}$$
D
$${a \over b}$$
2
WB JEE 2017
MCQ (Single Correct Answer)
+1
-0.25
Change Language
The line segment joining the foci of the hyperbola $${x^2} - {y^2} + 1 = 0$$ is one of the diameters of a circle. The equation of the circle is
A
$${x^2} + {y^2} = 4$$
B
$${x^2} + {y^2} = \sqrt 2 $$
C
$${x^2} + {y^2} = 2$$
D
$${x^2} + {y^2} = 2\sqrt 2 $$
3
WB JEE 2017
MCQ (Single Correct Answer)
+2
-0.5
Change Language
Let A($$-$$ 1, 0) and B(2, 0) be two points. A point M moves in the plane in such a way that $$\angle MBA$$ = 2$$\angle MAB$$. Then, the point M moves along
A
a straight line
B
a parabola
C
an ellipse
D
a hyperbola
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