WB JEE 2019 | Ellipse and Hyperbola Question 33 | Mathematics

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WB JEE 2019

MCQ (Single Correct Answer)

-0.25

The equation of the directrices of the hyperbola $$3{x^2} - 3{y^2} - 18x + 12y + 2 = 0$$ is

$$x = 3 \pm \sqrt {{{13} \over 6}} $$

$$x = 3 \pm \sqrt {{{6} \over 13}} $$

$$x = 6 \pm \sqrt {{{13} \over 3}} $$

$$x = 6 \pm \sqrt {{{3} \over 13}} $$

WB JEE 2019

MCQ (Single Correct Answer)

-0.25

P is the extremity of the latusrectum of ellipse $$3{x^2} + 4{y^2} = 48$$ in the first quadrant. The eccentric angle of P is

$${\pi \over 8}$$

$${{3\pi } \over 4}$$

$${\pi \over 3}$$

$${{2\pi } \over 3}$$

WB JEE 2019

MCQ (Single Correct Answer)

-0.5

The length of conjugate axis of a hyperbola is greater than the length of transverse axis. Then, the eccentricity e is

$$ = \sqrt 2 $$

$$ > \sqrt 2 $$

$$ < \sqrt 2 $$

$$ < {1 \over {\sqrt 2 }}$$

WB JEE 2019

MCQ (Single Correct Answer)

-0.5

A point is in motion along a hyperbola $$y = {{10} \over x}$$ so that its abscissa x increases uniformly at a rate of 1 unit per second. Then, the rate of change of its ordinate when the point passes through (5, 2)

increases at the rate of $${1 \over 2}$$ unit per second

decreases at the rate of $${1 \over 2}$$ unit per second

decreases at the rate of $${2 \over 5}$$ unit per second

increases at the rate of $${2 \over 5}$$ unit per second

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