1
WB JEE 2021
+1
-0.25
An element crystallises in a body centered cubic lattice. The edge length of the unit cell is 200 pm and the density of the element is 5.0 g cm$$-$$3. Calculate the number of atoms in 100 g of this element.
A
2.5 $$\times$$ 1023
B
2.5 $$\times$$ 1024
C
5.0 $$\times$$ 1023
D
5.0 $$\times$$ 1024
2
WB JEE 2020
+1
-0.25
In the face centered cubic lattice structure of gold the closest distance between gold atoms is ('a' being the edge length of the cubic unit cell)
A
$$a\sqrt 2$$
B
$${a \over {\sqrt 2 }}$$
C
$${a \over {2\sqrt 2 }}$$
D
$$2\sqrt 2 a$$
3
WB JEE 2018
+1
-0.33
A compound formed by elements X and Y crystallises in the cubic structure, where X atoms are at the corners of a cube and Y atoms are at the centre of the body. The formula of the compounds is
A
XY
B
XY2
C
X2Y3
D
XY3
4
WB JEE 2017
+2
-0.5
In a close-packed body-centred cubic lattice of potassium, the correct relation between the atomic radius (r) of potassium and the edge-length (a) of the cube is
A
$$r = {a \over {\sqrt 2 }}$$
B
$$r = {a \over {\sqrt 3 }}$$
C
$$r = {{\sqrt 3 } \over 2}a$$
D
$$r = {{\sqrt 3 } \over 4}a$$
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