1
MHT CET 2025 25th April Evening Shift
MCQ (Single Correct Answer)
+2
-0

The probability that a student is not a swimmer is $\frac{1}{5}$. The probability that out of 5 students selected at random 4 are swimmers is

A
$\left(\frac{4}{5}\right)^4$
B
$\left(\frac{4}{5}\right)^4\left(\frac{1}{5}\right)$
C
$\left(\frac{4}{5}\right)^5 \times \frac{1}{5}$
D
$\left(\frac{4}{5}\right)^3 \times \frac{1}{5^2}$
2
MHT CET 2025 25th April Evening Shift
MCQ (Single Correct Answer)
+2
-0

A player tosses two coins. He wins ₹ 10 , if 2 heads appears, ₹ 5 , if one head appear and ₹ 2 if no head appears. Then variance of winning amount is

A
38.5
B
8.25
C
5.5
D
44.00
3
MHT CET 2025 25th April Evening Shift
MCQ (Single Correct Answer)
+2
-0

Consider the probability distribution

$$ \begin{array}{|l|l|l|l|l|l|} \hline \mathrm{X}=x & 1 & 2 & 3 & 4 & 5 \\ \hline \mathrm{P}(\mathrm{X}=x) & \mathrm{K} & 2 \mathrm{~K} & \mathrm{~K}^2 & 2 \mathrm{~K} & 5 \mathrm{~K}^2 \\ \hline \end{array} $$

Then the value of $\mathrm{P}(\mathrm{X}>2)$ is

A
$\frac{7}{12}$
B
$\frac{1}{36}$
C
$\frac{1}{2}$
D
$\frac{23}{36}$
4
MHT CET 2025 25th April Evening Shift
MCQ (Single Correct Answer)
+2
-0

The equation of the curve passing through origin and satisfying $\left(1+x^2\right) \frac{\mathrm{d} y}{\mathrm{~d} x}+2 x y=4 x^2$ is

A
$y\left(1+x^2\right)=4 x^3$
B
$4\left(1+x^2\right)=4+y^2$
C
$3 y\left(1+x^2\right)=4 x^3$
D
$1+y^2=4 x^3+1$
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