1
MHT CET 2025 25th April Evening Shift
MCQ (Single Correct Answer)
+2
-0

If $y=\tan ^{-1}\left(\frac{12 x-64 x^3}{1-48 x^2}\right)$, then $\frac{\mathrm{d} y}{\mathrm{~d} x}=$

A
$\frac{3}{1+16 x^2}$
B
$\frac{4}{1+16 x^2}$
C
$\frac{12}{1+16 x^2}$
D
$\frac{1}{1+16 x^2}$
2
MHT CET 2025 25th April Evening Shift
MCQ (Single Correct Answer)
+2
-0

The order of the differential equation whose general solution is given by $y=\left(\mathrm{C}_1+\mathrm{C}_2\right) \sin \left(x+\mathrm{C}_3\right)-\mathrm{C}_4 \mathrm{e}^{x+\mathrm{C}_5}$ is (where $\mathrm{C}_1, \mathrm{C}_2, \mathrm{C}_3, \mathrm{C}_4, \mathrm{C}_5$ are arbitrary constants)

A
5
B
4
C
2
D
3
3
MHT CET 2025 25th April Evening Shift
MCQ (Single Correct Answer)
+2
-0

In L.P.P., the maximum value of objective function $\mathrm{Z}=6 x+3 y$ subject to constraints $x+y \leq 5, x+2 y \geq 4,4 x+y \leq 12, x, y \geq 0$ is

A
$\frac{132}{7}$
B
22
C
15
D
$\frac{122}{7}$
4
MHT CET 2025 25th April Evening Shift
MCQ (Single Correct Answer)
+2
-0

If the lines $x=a y-1=z-2$ and $x=3 y-2=\mathrm{bz}-2(\mathrm{ab} \neq 0)$ are coplanar, then

A
$\mathrm{a}=1, \mathrm{~b}=\frac{1}{2}$
B
$\mathrm{a}=2, \mathrm{~b}=2$
C
$\mathrm{a}=\frac{1}{2}, \mathrm{~b}=\frac{1}{2}$
D
$\mathrm{b}=1, \mathrm{a} \in \mathbb{R}-\{0\}$
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