MHT CET 2025 22nd April Evening Shift | MHT CET Year Wise Previous Years Questions

MHT CET 2025 22nd April Evening Shift

MCQ (Single Correct Answer)

-0

A thin metal wire of length ' L ' and mass ' M ' is bent to form semicircular ring as shown. The moment of inertia about $\mathrm{XX}^{\prime}$ is

MHT CET 2025 22nd April Evening Shift Physics - Rotational Motion Question 2 English

$\frac{\mathrm{ML}^2}{4 \pi^2}$

$\frac{2 M L^2}{\pi^2}$

$\frac{\mathrm{ML}^2}{2 \pi^2}$

$\frac{\mathrm{ML}^2}{\pi^2}$

MHT CET 2025 22nd April Evening Shift

MCQ (Single Correct Answer)

-0

A particle executes S.H.M. starting from the mean position. Its amplitude is ' a ' and its periodic time is ' $T$ '. At a certain instant, its speed ' $u$ ' is half that of maximum speed $\mathrm{V}_{\text {max }}$. The displacement of the particle at that instant is

$\frac{2 \mathrm{a}}{\sqrt{3}}$

$\frac{\sqrt{2} \mathrm{a}}{3}$

$\frac{3 \mathrm{a}}{\sqrt{2}}$

$\frac{\sqrt{3} \mathrm{a}}{2}$

MHT CET 2025 22nd April Evening Shift

MCQ (Single Correct Answer)

-0

Initially $n$ identical capacitors are joined in parallel and are charged to potential V. Now they are separated and joined in series. Then

potential difference and total energy of the combination remain the same.

potential difference remains the same and energy increases n times.

potential difference becomes nV and energy remains the same.

potential difference is nV and energy increases n times.

MHT CET 2025 22nd April Evening Shift

MCQ (Single Correct Answer)

-0

When the electron orbiting in hydrogen atom goes from one orbit to another orbit (principal quantum number $=n$ ), the de-Broglie wavelength ( $\lambda$ ) associated with it is related to $n$ as

$\lambda \propto \frac{1}{\mathrm{n}^2}$

$\lambda \propto n^2$

$\lambda \propto \frac{1}{n}$

$\lambda \propto \mathrm{n}$

PREVIOUS NEXT