1
MHT CET 2025 22nd April Evening Shift
MCQ (Single Correct Answer)
+1
-0

Initially $n$ identical capacitors are joined in parallel and are charged to potential V. Now they are separated and joined in series. Then

A
potential difference and total energy of the combination remain the same.
B
potential difference remains the same and energy increases n times.
C
potential difference becomes nV and energy remains the same.
D
potential difference is nV and energy increases n times.
2
MHT CET 2025 22nd April Evening Shift
MCQ (Single Correct Answer)
+1
-0

When the electron orbiting in hydrogen atom goes from one orbit to another orbit (principal quantum number $=n$ ), the de-Broglie wavelength ( $\lambda$ ) associated with it is related to $n$ as

A
$\lambda \propto \frac{1}{\mathrm{n}^2}$
B
$\lambda \propto n^2$
C
$\lambda \propto \frac{1}{n}$
D
$\lambda \propto \mathrm{n}$
3
MHT CET 2025 22nd April Evening Shift
MCQ (Single Correct Answer)
+1
-0

A constant force acts on two different masses independently and produces accelerations $\mathrm{A}_1$ and $A_2$. When the same force acts on their combined mass, the acceleration produced is

A
$\quad A_1-A_2$
B
$\mathrm{A}_1+\mathrm{A}_2$
C
$\frac{A_1 A_2}{A_1+A_2}$
D
$\sqrt{A_1^2+A_2^2}$
4
MHT CET 2025 22nd April Evening Shift
MCQ (Single Correct Answer)
+1
-0

When cell of e.m.f. ' $E_1$ ' is connected to potentiometer wire, the balancing length is ' $l_l$ '. Another cell of e.m.f. ' $E_2$ ' $\left(E_1>E_2\right)$ is connected so that two cells oppose each other, the balancing length is ' $l_1$ '. The ratio $E_1: E_2$ is

A
$\frac{l_1}{l_1+l_2}$
B
$\frac{l_1}{l_1-l_2}$
C
$\frac{l_1-l_2}{l_1}$
D
$\frac{l_1+l_2}{l_1-l_2}$
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