MHT CET 2024 9th May Evening Shift | MHT CET Year Wise Previous Years Questions

MHT CET 2024 9th May Evening Shift

MCQ (Single Correct Answer)

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Let $\mathrm{f}(x)=\mathrm{e}^x, \mathrm{~g}(x)=\sin ^{-1} x$ and $\mathrm{h}(x)=\mathrm{f}(\mathrm{g}(x))$, then $\left(\frac{h^{\prime}(x)}{h(x)}\right)^2$ is equal to

$\frac{1}{\sqrt{1-x^2}}$

$\left(1-x^2\right)^2$

$\frac{1}{1-x^2}$

$\left(1-x^2\right)$

MHT CET 2024 9th May Evening Shift

MCQ (Single Correct Answer)

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The joint equation of pair of lines through the origin and making an angle of $\frac{\pi}{6}$ with the line $3 x+y-6=0$ is

$13 x^2+12 x y+3 y^2=0$

$13 x^2-12 x y+3 y^2=0$

$13 x^2+12 x y-3 y^2=0$

$13 x^2-12 x y-3 y^2=0$

MHT CET 2024 9th May Evening Shift

MCQ (Single Correct Answer)

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A line $4 x+y=1$ passes through the point $\mathrm{A}(2,-7)$ meets the line BC whose equation is $3 x-4 y+1=0$ at the point $B$. The equation of the line $A C$ so that $A B=A C$ is

$52 x+89 y+519=0$

$52 x+89 y-727=0$

$52 x-89 y+519=0$

$52 x-89 y-727=0$

MHT CET 2024 9th May Evening Shift

MCQ (Single Correct Answer)

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The value of $\int \frac{\mathrm{d} x}{(x+1)^{3 / 4}(x-2)^{5 / 4}}$ is equal to

$4\left(\frac{x+1}{x-2}\right)^{1 / 4}+\mathrm{c}$, where c is a constant of integration.

$4\left(\frac{x-2}{x-1}\right)^{1 / 4}+\mathrm{c}$, where c is a constant of integration.

$\frac{-4}{3}\left(\frac{x-2}{x+1}\right)^{1 / 4}+\mathrm{c}$, where c is a constant of integration.

$\frac{-4}{3}\left(\frac{x+1}{x-2}\right)^{1 / 4}+\mathrm{c}$, where c is a constant of integration.