1
MHT CET 2024 4th May Morning Shift
MCQ (Single Correct Answer)
+2
-0

The integral $\int \sec ^{\frac{2}{3}} x \cdot \operatorname{cosec}^{\frac{4}{3}} x \mathrm{~d} x$ is equal to

A
$3(\tan x)^{-\frac{1}{3}}+\mathrm{c}$, (where c is the constant of integration)
B
$-\frac{3}{4}(\tan x)^{\frac{4}{3}}+\mathrm{c},($ where c is the constant of integration)
C
$-3(\cot x)^{\frac{1}{3}}+\mathrm{c},($ where c is the constant of integration)
D
$-3(\tan x)^{\frac{1}{3}}+\mathrm{c}$, (where c is the constant of integration)
2
MHT CET 2024 4th May Morning Shift
MCQ (Single Correct Answer)
+2
-0

If sum of two numbers is 3 , then the maximum value of the product of first number and square of the second number is

A
6
B
4
C
5
D
3
3
MHT CET 2024 4th May Morning Shift
MCQ (Single Correct Answer)
+2
-0

Given that the slope of the tangent to a curve $y=y(x)$ at any point $(x, y)$ is $\frac{2 y}{x^2}$. If the curve passes through the centre of the circle $x^2+y^2-2 x-2 y=0$, then its equation is

A
$x \log |y|=x-1$
B
$x \log |y|=-2(x-1)$
C
$x \log |y|=2(x-1)$
D
$x^2 \log |y|=-2(x-1)$
4
MHT CET 2024 4th May Morning Shift
MCQ (Single Correct Answer)
+2
-0

If $y=\left((x+1)(4 x+1)(9 x+1) \ldots\left(\mathrm{n}^2 x+1\right)\right)^2$, then $\frac{\mathrm{dy}}{\mathrm{d} x}$ at $x=0$ is

A
$\frac{\mathrm{n}(\mathrm{n}+1)(2 \mathrm{n}+1)}{4}$
B
$\frac{\mathrm{n}(\mathrm{n}+1)(2 \mathrm{n}+1)}{6}$
C
$\frac{\mathrm{n}(\mathrm{n}+1)(2 \mathrm{n}+1)}{2}$
D
$\frac{\mathrm{n}(\mathrm{n}+1)(2 \mathrm{n}+1)}{3}$
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