1
MHT CET 2024 4th May Morning Shift
MCQ (Single Correct Answer)
+2
-0

The lines $\frac{x-2}{1}=\frac{y-3}{1}=\frac{z-4}{-k} \quad$ and $\frac{x-1}{\mathrm{k}}=\frac{y-4}{2}=\frac{\mathrm{z}-5}{1}$ are coplanar if

A
$\mathrm{k}=1$ or $\mathrm{k}=-1$
B
$\mathrm{k}=0$ or $\mathrm{k}=-3$
C
$\mathrm{k}=3$ or $\mathrm{k}=-3$
D
$\mathrm{k}=0$ or $\mathrm{k}=3$
2
MHT CET 2024 4th May Morning Shift
MCQ (Single Correct Answer)
+2
-0

The variance of first 50 even natural numbers is

A
833
B
473
C
$\frac{437}{4}$
D
$\frac{833}{4}$
3
MHT CET 2024 4th May Morning Shift
MCQ (Single Correct Answer)
+2
-0

The statement pattern $[p \wedge(q \vee r)] \vee[\sim r \wedge \sim q \wedge p]$ is equivalent to

A
$q \vee r$
B
$\mathrm{p} \vee \mathrm{r}$
C
$q$
D
$p$
4
MHT CET 2024 4th May Morning Shift
MCQ (Single Correct Answer)
+2
-0

If $8 \mathrm{f}(x)+6 \mathrm{f}\left(\frac{1}{x}\right)=x+5$ and $y=x^2 \mathrm{f}(x)$, then $\frac{\mathrm{d} y}{\mathrm{~d} x}$ at $x=-1$ is

A
14
B
$-$14
C
$\frac{1}{14}$
D
$-\frac{1}{14}$
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