1
MHT CET 2024 4th May Morning Shift
MCQ (Single Correct Answer)
+2
-0

Suppose A is any $3 \times 3$ non-singular matrix and $(\mathrm{A}-3 \mathrm{I})(\mathrm{A}-5 \mathrm{I})=0$ where $\mathrm{I}=\mathrm{I}_3$ and $\mathrm{O}=\mathrm{O}_3$. Here $\mathrm{O}_3$ represent zero matrix of order 3 and $\mathrm{I}_3$ is an identity matrix of order 3 . If $\alpha A+\beta A^{-1}=4 I$, then $\alpha+\beta$ is equal to

A
13
B
7
C
12
D
8
2
MHT CET 2024 4th May Morning Shift
MCQ (Single Correct Answer)
+2
-0

The lines $\frac{x-2}{1}=\frac{y-3}{1}=\frac{z-4}{-k} \quad$ and $\frac{x-1}{\mathrm{k}}=\frac{y-4}{2}=\frac{\mathrm{z}-5}{1}$ are coplanar if

A
$\mathrm{k}=1$ or $\mathrm{k}=-1$
B
$\mathrm{k}=0$ or $\mathrm{k}=-3$
C
$\mathrm{k}=3$ or $\mathrm{k}=-3$
D
$\mathrm{k}=0$ or $\mathrm{k}=3$
3
MHT CET 2024 4th May Morning Shift
MCQ (Single Correct Answer)
+2
-0

The variance of first 50 even natural numbers is

A
833
B
473
C
$\frac{437}{4}$
D
$\frac{833}{4}$
4
MHT CET 2024 4th May Morning Shift
MCQ (Single Correct Answer)
+2
-0

The statement pattern $[p \wedge(q \vee r)] \vee[\sim r \wedge \sim q \wedge p]$ is equivalent to

A
$q \vee r$
B
$\mathrm{p} \vee \mathrm{r}$
C
$q$
D
$p$
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