1
MHT CET 2024 16th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

The power radiated by a black body is P and it radiates maximum energy around the wavelength $\lambda_0$. Now the temperature of the black body is changed so that it radiates maximum energy around wavelength $\left(\frac{\lambda_0}{2}\right)$. The power radiated by it will now increase by a factor of

A
2
B
8
C
16
D
32
2
MHT CET 2024 16th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

Two coils P and Q each of radius R carry currents I and $\sqrt{8} \mathrm{I}$ respectively in same direction. Those coils are lying in perpendicular planes such that they have a common centre. The magnitude of the magnetic field at the common centre of the two coils is ( $\mu_0=$ permeability of free space)

A
$\frac{\mu_0 I}{2 R}$
B
$\frac{3 \mu_0 I}{2 R}$
C
$\frac{5 \mu_0 I}{2 R}$
D
$\frac{7 \mu_0 \mathrm{I}}{2 \mathrm{R}}$
3
MHT CET 2024 16th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

In Young's double slit experiment, intensity at a point is $\left(\frac{1}{4}\right)$ of the maximum intensity. The angular position of this point is

A
$\sin ^{-1}\left(\frac{\lambda}{D}\right)$
B
$\sin ^{-1}\left(\frac{\lambda}{2 d}\right)$
C
$\sin ^{-1}\left(\frac{\lambda}{3 \mathrm{~d}}\right)$
D
$\sin ^{-1}\left(\frac{\lambda}{4 d}\right)$
4
MHT CET 2024 16th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

The mutual inductance of two coils is 45 mH . The self-inductance of the coils are $\mathrm{L}_1=75 \mathrm{mH}$ and $\mathrm{L}_2=48 \mathrm{mH}$. The coefficient of coupling between the two coils is

A
0.3
B
0.4
C
0.75
D
1.0
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