1
MHT CET 2024 16th May Morning Shift
MCQ (Single Correct Answer)
+1
-0
 

Two identical capacitors A and B are connected in series to a battery of E.M.F., 'E'. Capacitor B contains a slab of dielectric constant $\mathrm{K} . \mathrm{Q}_{\mathrm{A}}$ and $\mathrm{Q}_{\mathrm{B}}$ are the charges stored in A and B . When the dielectric slab is removed, the corresponding charges are $\mathrm{Q}_{\mathrm{A}}^{\prime}$ and $\mathrm{Q}_{\mathrm{B}}^{\prime}$. Then

A
$\mathrm{\frac{Q_A^{\prime}}{Q_A}=\frac{K}{2}}$
B
$\frac{\mathrm{Q}_{\mathrm{B}}^{\prime}}{\mathrm{Q}_{\mathrm{B}}}=\frac{\mathrm{K}+1}{2}$
C
$\frac{\mathrm{Q}_{\mathrm{A}}^{\prime}}{\mathrm{Q}_{\mathrm{A}}}=\frac{\mathrm{K}+1}{\mathrm{~K}}$
D
$\frac{\mathrm{Q}_{\mathrm{B}}^{\prime}}{\mathrm{Q}_{\mathrm{B}}}=\frac{\mathrm{K}+1}{2 \mathrm{~K}}$
2
MHT CET 2024 16th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

In $\mathrm{M}_{\mathrm{O}}$ is the mass of an oxygen isotope ${ }_8 \mathrm{O}^{17}$ and $\mathrm{M}_{\mathrm{p}}$ and $\mathrm{M}_{\mathrm{N}}$ are the mass of proton and mass of neutron respectively, then the nucleus binding energy of the isotope is

A
$\mathrm{M}_{\mathrm{o}} \mathrm{C}^2$
B
$\left(\mathrm{M}_{\mathrm{o}}-8 \mathrm{M}_{\mathrm{P}}\right) \mathrm{C}^2$
C
$\mathrm{\left(M_o-17 M_N\right) C^2}$
D
$\left(\mathrm{M}_{\mathrm{o}}-8 \mathrm{M}_{\mathrm{P}}-9 \mathrm{M}_{\mathrm{N}}\right) \mathrm{C}^2$
3
MHT CET 2024 16th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

Two point charges $+8 q$ and $-2 q$ are located at $x=0$ and $x=\mathrm{L}$ respectively. The location of a point on the $x$-axis from the origin, at which the net electric field due to these two point charges is zero is

A
$\frac{\mathrm{L}}{4}$
B
$\mathrm{4 L}$
C
$\mathrm{8 L}$
D
$\mathrm{2 L}$
4
MHT CET 2024 16th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

When an electron orbiting in hydrogen atom in its ground state jumps to higher excited state, the de-Broglie wavelength associated with it

A
will become zero.
B
will remain same.
C
will decrease.
D
will increase.
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