MHT CET 2024 15th May Evening Shift | MHT CET Year Wise Previous Years Questions

MHT CET 2024 15th May Evening Shift

MCQ (Single Correct Answer)

-0

The figure shows currents in a part of electric circuit. Then current I is

MHT CET 2024 15th May Evening Shift Physics - Current Electricity Question 32 English

3.5 A

1.5 A

4 A

2.5 A

MHT CET 2024 15th May Evening Shift

MCQ (Single Correct Answer)

-0

A metal disc of radius R rotates with an angular velocity $\omega$ about an axis perpendicular to its plane passing through its centre in a magnetic field of induction B acting perpendicular to the plane of the disc. The induced e.m.f. between the rim and axis of the disc is

$\mathrm{B} \pi \mathrm{R}^2$

$\frac{2 \mathrm{~B} \pi^2 \mathrm{R}^2}{\omega}$

$\mathrm{B} \pi \mathrm{R}^2 \omega$

$\frac{\mathrm{BR}^2 \omega}{2}$

MHT CET 2024 15th May Evening Shift

MCQ (Single Correct Answer)

-0

A body of mass $m$ slides down an incline and reaches the bottom with a velocity V . If the same mass were in the form of a disc which rolls down this incline, the velocity of the disc at bottom would have been

$\mathrm{v} \sqrt{\frac{3}{4}}$

$\mathrm{v} \sqrt{\frac{3}{2}}$

$v \sqrt{\frac{1}{3}}$

$\mathrm{v} \sqrt{\frac{2}{3}}$

MHT CET 2024 15th May Evening Shift

MCQ (Single Correct Answer)

-0

For a particle executing S.H.M. having amplitude A, the speed of the article is $\left(\frac{1}{3}\right)^{\text {rd }}$ of its maximum speed when the displacement from the mean position is

$\frac{3 \mathrm{~A}}{\sqrt{2}}$

$\frac{2 \mathrm{~A}}{3}$

$\frac{2 \sqrt{2}}{3} \mathrm{~A}$

$\frac{\sqrt{2}}{3} \mathrm{~A}$

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