MHT CET 2024 15th May Evening Shift | MHT CET Year Wise Previous Years Questions

MHT CET 2024 15th May Evening Shift

MCQ (Single Correct Answer)

-0

A wave is given by $Y=3 \sin 2 \pi\left(\frac{t}{0.04}-\frac{x}{0.01}\right)$ where Y is in cm . Frequency of the wave and maximum acceleration will be $\left(\pi^2=10\right)$

$100 \mathrm{~Hz}, 4.7 \times 10^4 \mathrm{~cm} / \mathrm{s}^2$

$50 \mathrm{~Hz}, 7.5 \times 10^3 \mathrm{~cm} / \mathrm{s}^2$

$25 \mathrm{~Hz}, 4.7 \times 10^4 \mathrm{~cm} / \mathrm{s}^2$

$25 \mathrm{~Hz}, 7.5 \times 10^4 \mathrm{~cm} / \mathrm{s}^2$

MHT CET 2024 15th May Evening Shift

MCQ (Single Correct Answer)

-0

Two concentric circular coils A and B having radii 20 cm and 10 cm respectively lie in the same plane. The current in coil A is 0.5 A in anticlockwise direction. The current in coil B , so that net magnetic field at the common centre is zero, is

$0.5 \mathrm{~A}$ in anticlockwise direction.

0.25 A in anticlockwise direction.

0.25 A in clockwise direction.

0.125 A in clockwise direction.

MHT CET 2024 15th May Evening Shift

MCQ (Single Correct Answer)

-0

The radius of gyration of a circular disc of radius R and mass m rotating about diameter as axis is

$\mathrm{R} \sqrt{2}$

$\mathrm{R} / \sqrt{2}$

$\mathrm{R} / 2$

$\mathrm{R}$