GATE EE 2009 | GATE EE Year Wise Previous Years Questions

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GATE EE 2009

MCQ (Single Correct Answer)

-0.6

In $$8085$$ microprocessor, the contents of the Accumulator, after the following instructions are executed will become

$$\eqalign{ & XRA\,\,\,A \cr & MVI\,\,\,B\,\,\,F0\,\,\,H \cr & SUB\,\,\,B \cr} $$

$$01$$ $$H$$

$$0F$$ $$H$$

$$F0$$ $$H$$

$$10$$ $$H$$

GATE EE 2009

MCQ (Single Correct Answer)

-0.6

For the circuit shown, find out the current flowing through the $$2\Omega $$ resistance. Also identify the changes to be made to double the current through the $$2\Omega $$ resistance. GATE EE 2009 Electric Circuits - Network Elements Question 6 English

GATE EE 2009 Electric Circuits - Network Elements Question 6 English

$$\left( {5\,\,A;\,\,Put\,\,{V_S} = 20\,\,V} \right)$$

$$\left( {2\,\,A;\,\,Put\,\,{V_S} = 8\,\,V} \right)$$

$$\left( {5\,\,A;\,\,Put\,\,{{\rm I}_S} = 10\,\,A} \right)$$

$$\left( {7\,\,A;\,\,Put\,\,{{\rm I}_S} = 12\,\,A} \right)$$

GATE EE 2009

MCQ (Single Correct Answer)

-0.3

The current through the $$2\,\,k\Omega $$ resistance in the circuit shown in Fig. is GATE EE 2009 Electric Circuits - Network Elements Question 15 English

$$0$$ $$mA$$

$$1$$ $$mA$$

$$2$$ $$mA$$

$$6$$ $$mA$$

GATE EE 2009

MCQ (Single Correct Answer)

-0.6

The equivalent capacitance of the input loop of the circuit shown in below GATE EE 2009 Electric Circuits - Network Elements Question 7 English

$$2\,\,\mu F$$

$$100\,\,\mu F$$

$$200\,\,\mu F$$

$$4\,\,\mu F$$

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