1
GATE CSE 2004
MCQ (Single Correct Answer)
+2
-0.6
The time complexity of the following C function is (assume n > 0)
int recursive(int n){
 if(n == 1){
   return (1);
 }
 return (recursive(n - 1) + recursive(n - 1));
}
A
O(n)
B
O(n log n)
C
O(n2)
D
O(2n)
2
GATE CSE 2004
MCQ (Single Correct Answer)
+2
-0.6
Let A[1,...,n] be an array storing a bit (1 or 0) at each location, and f(m) is a function whose time complexity is O(m). Consider the following program fragment written in a C like language:
counter = 0;
for(i = 1; i <= n; i++){
 if(A[i]==1){
   counter++;
 }else{
   f(counter); counter = 0;
 }
}
The complexity of this program fragment is
A
$$\Omega ({n^2})$$
B
$$\Omega (n\,\log n)\,and\,O({n^2})$$
C
$$\theta (n)$$
D
$$O(n)$$
3
GATE CSE 2004
MCQ (Single Correct Answer)
+1
-0.3
The tightest lower bound on the number of comparisons, in the worst case, for comparison-based sorting is of the order of
A
$$n$$
B
$${n^2}$$
C
$$n\log n$$
D
$$n{\log ^2}n$$
4
GATE CSE 2004
MCQ (Single Correct Answer)
+1
-0.3
Consider the grammar rule $$E \to {E_1} - {E_2}$$ for arithmetic expressions. The code generated is targeted to a CPU having a single user register. The subtraction operation requires the first operand to be in the register. If E1 and E2 do not have any common sub-expression, in order to get the shortest possible code.
A
E1 should be evaluated first
B
E2 should be evaluated first
C
Evaluation of E1 and E2 should necessarily be interleaved
D
Order to evaluation of E1 and E2 is of no consequence
EXAM MAP