WB JEE 2017 | Simple Harmonic Motion Question 8 | Physics

WB JEE 2017

MCQ (Single Correct Answer)

-0.25

The velocity of a particle executing a simple harmonic motion is 13 ms^$$-$$1, when its distance from the equilibrium position (Q) is 3 m and its velocity is 12 ms^$$-$$1, when it is 5 m away from Q. The frequency of the simple harmonic motion is

$${{5\pi } \over 8}$$

$${5 \over {8\pi }}$$

$${{8\pi } \over 5}$$

$${8 \over {5\pi }}$$

WB JEE 2017

MCQ (Single Correct Answer)

-0.25

A uniform string of length L and mass M is fixed at both ends while it is subject to a tension T. It can vibrate at frequencies (v) given by the formula (where n = 1, 2, 3, ....)

$$v = {n \over 2}\sqrt {{T \over {ML}}} $$

$$v = {n \over {2L}}\sqrt {{T \over M}} $$

$$v = {1 \over {2n}}\sqrt {{T \over {ML}}} $$

$$v = {n \over 2}\sqrt {{{TL} \over M}} $$

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