1
WB JEE 2020
MCQ (Single Correct Answer)
+1
-0.25
Change Language
The bob of a swinging second pendulum (one whose time period is 2 s) has a small speed v0 at its lowest point. It height from this lowest point 2.25 s after passing through it, is given by
A
$${{v_0^2} \over {2g}}$$
B
$${{v_0^2} \over {g}}$$
C
$${{v_0^2} \over {4g}}$$
D
$${{9v_0^2} \over {4g}}$$
2
WB JEE 2018
MCQ (Single Correct Answer)
+1
-0.25
Change Language
In case of a simple harmonic motion, if the velocity is plotted along the X-axis and the displacement (from the equilibrium position) is plotted along the Y-axis, the resultant curve happens to be an ellipse with the ratio $${{major\,axis\,(along\,X)} \over {minor\,axis\,(along\,Y)}} = 20\pi $$

What is the frequency of the simple harmonic motion?
A
100 Hz
B
20 Hz
C
10 Hz
D
$${1 \over {10}}$$ Hz
3
WB JEE 2017
MCQ (Single Correct Answer)
+1
-0.25
Change Language
The velocity of a particle executing a simple harmonic motion is 13 ms$$-$$1, when its distance from the equilibrium position (Q) is 3 m and its velocity is 12 ms$$-$$1, when it is 5 m away from Q. The frequency of the simple harmonic motion is
A
$${{5\pi } \over 8}$$
B
$${5 \over {8\pi }}$$
C
$${{8\pi } \over 5}$$
D
$${8 \over {5\pi }}$$
4
WB JEE 2017
MCQ (Single Correct Answer)
+1
-0.25
Change Language
A uniform string of length L and mass M is fixed at both ends while it is subject to a tension T. It can vibrate at frequencies (v) given by the formula (where n = 1, 2, 3, ....)
A
$$v = {n \over 2}\sqrt {{T \over {ML}}} $$
B
$$v = {n \over {2L}}\sqrt {{T \over M}} $$
C
$$v = {1 \over {2n}}\sqrt {{T \over {ML}}} $$
D
$$v = {n \over 2}\sqrt {{{TL} \over M}} $$
WB JEE Subjects
EXAM MAP
Medical
NEET
Graduate Aptitude Test in Engineering
GATE CSEGATE ECEGATE EEGATE MEGATE CEGATE PIGATE IN
CBSE
Class 12