The mean deviation about the mean for the following data is \begin{array}{c|l|l|l|l|l} \hline \text { Class interval } & 0-2 & 2-4 & 4-6 & 6-8 & 8-10 \\\\ \hline \text { Frequency } & 1 & 3 & 5 & 3 & 1 \\\\ \hline \end{array}

The mean and standard deviation of 100 observations were calculated as 40 and 5.1 respectively. Later on it was found that one of the observations was taken as 50 in the place of 40 . If the wrong entry is replaced by the correct one, then the sum of the squares of all the observations is

The variance of 50 observations is 7 . Suppose that each observation in this data is multiplied by 6 and then 5 is subtracted from it. Then, the variance of that new data is

If $M$ and $\sigma^2$ represent respectively the mean deviation from the mean and the variance for the data $1,3,5,7$, $11,13,17,19,23$, then $3\left(\sigma^2-M\right)=$