If $M_1$ is the mean deviation from the mean of the discrete data $44,5,27,20,8,54,9,14,35$ and $M_2$ is the mean deviation from the median of the same data, then $M_1-M_2=$

The mean of a binomial variate $X \sim B(n, p)$ is 1 . If $n>2$ and $P(X=2)=\frac{27}{128}$, then the variance of the distribution is

The variance of the following continuous frequency distribution is

Classinterval	0-4	4-8	8-12	12-16
Frequency	2	3	2	1

The mean deviation about the mean for the following data is \begin{array}{c|l|l|l|l|l} \hline \text { Class interval } & 0-2 & 2-4 & 4-6 & 6-8 & 8-10 \\\\ \hline \text { Frequency } & 1 & 3 & 5 & 3 & 1 \\\\ \hline \end{array}