WB JEE 2017 | Hyperbola Question 25 | Mathematics

WB JEE 2017

MCQ (Single Correct Answer)

-0.25

The line segment joining the foci of the hyperbola $${x^2} - {y^2} + 1 = 0$$ is one of the diameters of a circle. The equation of the circle is

$${x^2} + {y^2} = 4$$

$${x^2} + {y^2} = \sqrt 2 $$

$${x^2} + {y^2} = 2$$

$${x^2} + {y^2} = 2\sqrt 2 $$

WB JEE 2017

MCQ (Single Correct Answer)

-0.5

Let A($$-$$ 1, 0) and B(2, 0) be two points. A point M moves in the plane in such a way that $$\angle MBA$$ = 2$$\angle MAB$$. Then, the point M moves along

a straight line

a parabola

an ellipse

a hyperbola

WB JEE 2016

MCQ (Single Correct Answer)

-0.25

If PQ is a double ordinate of the hyperbola $${{{x^2}} \over {{a^2}}} - {{{y^2}} \over {{b^2}}} = 1$$ such that $$\Delta OPQ$$ is equilateral. O being the centre. Then, the eccentricity e satisfies

$$1 < e < {2 \over {\sqrt 3 }}$$

$$e = {2 \over {\sqrt 2 }}$$

$$e = {{\sqrt 3 } \over 2}$$

$$e > {2 \over {\sqrt 3 }}$$

WB JEE Subjects