1
WB JEE 2012
MCQ (Single Correct Answer)
+1
-0.33
The general solution of the differential equation $${{dy} \over {dx}} = {{x + y + 1} \over {2x + 2y + 1}}$$ is
A
$${\log _e}|3x + 3y + 2| + 3x + 6y = C$$
B
$${\log _e}|3x + 3y + 2| - 3x + 6y = C$$
C
$${\log _e}|3x + 3y + 2| - 3x - 6y = C$$
D
$${\log _e}|3x + 3y + 2| + 3x - 6y = C$$
2
WB JEE 2024
MCQ (Single Correct Answer)
+1
-0.25
Change Language

Let $$\mathrm{f}$$ be a differential function with $$\lim _\limits{x \rightarrow \infty} \mathrm{f}(x)=0$$. If $$\mathrm{y}^{\prime}+\mathrm{yf}^{\prime}(x)-\mathrm{f}(x) \mathrm{f}^{\prime}(x)=0$$, $$\lim _\limits{x \rightarrow \infty} y(x)=0$$ then

A
$$\mathrm{y}+1=\mathrm{e}^{\mathrm{f}(x)}+\mathrm{f}(x)$$
B
$$\mathrm{y}+1=\mathrm{e}^{-\mathrm{f}(x)}+\mathrm{f}(x)$$
C
$$\mathrm{y}+2=\mathrm{e}^{-\mathrm{f}(\mathrm{x})}+\mathrm{f}(x)$$
D
$$\mathrm{y}-1=\mathrm{e}^{-\mathrm{f}(x)}+\mathrm{f}(x)$$
3
WB JEE 2024
MCQ (Single Correct Answer)
+1
-0.25
Change Language

If $$x y^{\prime}+y-e^x=0, y(a)=b$$, then $$\lim _\limits{x \rightarrow 1} y(x)$$ is

A
$$e+2 a b-e^a$$
B
$$e^2+a b-e^{-a}$$
C
$$\mathrm{e}-\mathrm{ab}+\mathrm{e}^{\mathrm{a}}$$
D
$$\mathrm{e}+\mathrm{ab}-\mathrm{e}^{\mathrm{a}},\left(\mathrm{y}^{\prime}=\frac{\mathrm{dy}}{\mathrm{d} x}\right)$$
4
WB JEE 2023
MCQ (Single Correct Answer)
+1
-0.25
Change Language

If $$y = {x \over {{{\log }_e}|cx|}}$$ is the solution of the differential equation $${{dy} \over {dx}} = {y \over x} + \phi \left( {{x \over y}} \right)$$, then $$\phi \left( {{x \over y}} \right)$$ is given by

A
$${{{y^2}} \over {{x^2}}}$$
B
$$ - {{{y^2}} \over {{x^2}}}$$
C
$${{{x^2}} \over {{y^2}}}$$
D
$$ - {{{x^2}} \over {{y^2}}}$$
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