1
WB JEE 2009
MCQ (Single Correct Answer)
+1
-0.25

The slope at any point of a curve y = f(x) is given by $${{dy} \over {dx}} = 3{x^2}$$ and it passes through ($$-$$1, 1). The equation of the curve is

A
y = x3 + 2
B
y = $$-$$x3 + 4
C
y = 3x2 + 4
D
y = $$-$$x3 $$-$$ 2
2
WB JEE 2009
MCQ (Single Correct Answer)
+1
-0.25

The general solution of the differential equation $${{dy} \over {dx}} = {e^{y + x}} + {e^{y - x}}$$ is

where c is an arbitrary constant

A
$${e^{ - y}} = {e^x} - {e^{ - x}} + c$$
B
$${e^{ - y}} = {e^{ - x}} - {e^x} + c$$
C
$${e^{ - y}} = {e^x} + {e^{ - x}} + c$$
D
$${e^y} = {e^x} + {e^{ - x}} + c$$
3
WB JEE 2009
MCQ (Single Correct Answer)
+1
-0.25

The integrating factor of the differential equation $$x\log x{{dy} \over {dx}} + y = 2\log x$$ is given by

A
ex
B
log x
C
log(log x)
D
x
4
WB JEE 2009
MCQ (Single Correct Answer)
+1
-0.25

If x2 + y2 = 1, then

A
yy'' $$-$$ (2y')2 + 1 = 0
B
yy'' + (y')2 + 1 = 0
C
yy'' $$-$$ (y')2 $$-$$ 1 = 0
D
yy'' + 2(y')2 + 1 = 0
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Medical
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Graduate Aptitude Test in Engineering
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CBSE
Class 12