WB JEE 2009 | Differential Equations Question 10 | Mathematics

WB JEE 2009

MCQ (Single Correct Answer)

-0.25

The general solution of the differential equation $${{dy} \over {dx}} = {e^{y + x}} + {e^{y - x}}$$ is

where c is an arbitrary constant

$${e^{ - y}} = {e^x} - {e^{ - x}} + c$$

$${e^{ - y}} = {e^{ - x}} - {e^x} + c$$

$${e^{ - y}} = {e^x} + {e^{ - x}} + c$$

$${e^y} = {e^x} + {e^{ - x}} + c$$

WB JEE 2009

MCQ (Single Correct Answer)

-0.25

The integrating factor of the differential equation $$x\log x{{dy} \over {dx}} + y = 2\log x$$ is given by

e^x

log x

log(log x)

WB JEE 2009

MCQ (Single Correct Answer)

-0.25

If x² + y² = 1, then

yy'' $$-$$ (2y')² + 1 = 0

yy'' + (y')² + 1 = 0

yy'' $$-$$ (y')² $$-$$ 1 = 0

yy'' + 2(y')² + 1 = 0

WB JEE 2009

MCQ (Single Correct Answer)

-0.25

The order of the differential equation $${{{d^2}y} \over {d{x^2}}} = \sqrt {1 + {{\left( {{{dy} \over {dx}}} \right)}^2}} $$ is

WB JEE Subjects