The area (in sq. units) of the portion lying above the $X$-axis and enclosed between the curves $y^2=2 a x-x^2$ and $y^2=a x$ is

The area (in square units) of the region enclosed between the parabola $y^2=2 x$ and the line $y=4 x-1$

If the area of the region bounded by $y=\cos x, y=\sin x$, $x=\pi / 4$ and $x=\pi$ is bisected by the line $x=a$, then $\sin \left(a+\frac{\pi}{4}\right)=$