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TS EAMCET 2020 (Online) 10th September Morning Shift
MCQ (Single Correct Answer)
+1
-0

If the area of the region bounded by $y=\cos x, y=\sin x$, $x=\pi / 4$ and $x=\pi$ is bisected by the line $x=a$, then $\sin \left(a+\frac{\pi}{4}\right)=$

A

$\frac{\sqrt{2}}{2+\sqrt{2}}$

B

$\frac{\sqrt{3}+1}{2}$

C

$\frac{\sqrt{2}-1}{2 \sqrt{2}}$

D

$\frac{\sqrt{3}+1}{2 \sqrt{2}}$

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