Statement I The set of solutions of $|x|^2-4|x|+3<0$ is the interval $(-3,3)$

Statement II If $x<3$ or $x>5$, then $x^2-8 x+15>0$

Which of the above statements is (are) true?

If $6 x-x^2+12$ attains its extreme value $\beta$ at $x=\alpha$, then $\beta=$

Let $a$ be a common root of the equations $x^3-2 x-25 \lambda=0,3 x^3-8 x-\frac{175}{3} \lambda=0$ and $\lambda>0$. Then, $\lambda=$

If the sum of two roots of the equation $x^3-7 p x^2+5 q x-6 r=0$ is zero, then