$\left(x^4+1\right)=\frac{1}{a}(x+1)^4$ is a reciprocal equation

Let $f(x)=A x^2+B x, g(x)=L x^2+M x+N$. Given that $f(2)-g(2)=1, f(3)-g(3)=4, f(4)-g(4)=9$. Then, a root of $f(x)-g(x)=0$ is

If $f(x)=\frac{2 x-3}{(x-2)(x-3)}$ is a real valued function, then the value that $f(x)$ does not take is

If $\alpha, \beta$ and $\gamma$ are the roots of the equation $5 x^3-3 x^2+2 x-4=0$, then $\Sigma \alpha^2 \beta^2=$