1
TS EAMCET 2020 (Online) 14th September Evening Shift
MCQ (Single Correct Answer)
+1
-0

If tangents are drawn to the ellipse $x^2+2 y^2=2$, then the locus of the mid-points of the intercepts made by those tangents between the coordinate axes is

A

$\frac{x^2}{2}+\frac{y^2}{4}=1$

B

$\frac{x^2}{4}+\frac{y^2}{2}=1$

C

$\frac{1}{2 x^2}+\frac{1}{4 y^2}=1$

D

$\frac{1}{4 x^2}+\frac{1}{2 y^2}=1$

2
TS EAMCET 2020 (Online) 14th September Evening Shift
MCQ (Single Correct Answer)
+1
-0

The area (in sq. units) of the quadrilateral formed by the tangents drawn at the end points of the latus rectum to the ellipse $S \equiv \frac{x^2}{16}+\frac{y^2}{12}=1$ is

A

96

B

16

C

128

D

64

3
TS EAMCET 2020 (Online) 14th September Morning Shift
MCQ (Single Correct Answer)
+1
-0

Equation of a common tangent to the circle $x^2+y^2=4$ and to the ellipse $2 x^2+25 y^2=50$ is

A

$\sqrt{2} x+\sqrt{21} y+\sqrt{23}=0$

B

$\sqrt{2} x-\sqrt{21} y+2 \sqrt{23}=0$

C

$\sqrt{19} x-\sqrt{2} y+2 \sqrt{21}=0$

D

$\sqrt{19} x-y+2 \sqrt{20}=0$

4
TS EAMCET 2020 (Online) 14th September Morning Shift
MCQ (Single Correct Answer)
+1
-0

The $\theta$ is the angle made by the common tangent to the circle $x^2+y^2=16$ and the ellipse $\frac{x^2}{25}+\frac{y^2}{9}=1$ with positive $X$-axis, then $\cos 2 \theta=$

A

$\frac{-2}{3}$

B

$\frac{5}{6}$

C

$\frac{-1}{8}$

D

$\frac{1}{8}$

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