If $f(x)=\frac{2 x-3}{(x-2)(x-3)}$ is a real valued function, then the value that $f(x)$ does not take is

If $\alpha, \beta$ and $\gamma$ are the roots of the equation $5 x^3-3 x^2+2 x-4=0$, then $\Sigma \alpha^2 \beta^2=$

If $\alpha, \beta$ and $\gamma$ are the roots of the equation $x^3+4 x^2-9 x-36=0$ such that $\alpha+\beta=0$, then $\alpha^2+2 \beta^2+3 \gamma^2=$

If $m$ and $M$ are respectively, the smallest and greatest rational roots of the equation $6 x^6-25 x^5+31 x^4-31 x^2+25 x-6=0$, then $M-m=$