$\frac{2^x}{\log 2}-\sin x+\cos x-\frac{1}{x}-\log x+c$

$2^x \log 2+\sin x-\cos x-\frac{1}{x}+\frac{1}{x^2}+c$

$\frac{2^x}{\log 2}+\sin x-\cos x-\frac{1}{x}-\log x+c$

$2^x \log 2-\sin x+\cos x-\frac{1}{x}+\frac{1}{x^2}+c$

$\frac{1}{5} \log \left|\tan \left(\frac{x}{2}+\frac{\alpha}{2}\right)\right|+c$

$\frac{1}{5} \log \left|\tan \left(\frac{\pi}{4}+\frac{x}{2}+\frac{\alpha}{2}\right)\right|+c$

$\frac{1}{5} \log \left|\tan \left(\frac{\pi}{4}-\frac{x}{2}-\frac{\alpha}{2}\right)\right|+c$

$\frac{1}{5} \log |\tan (\sec x+\tan x)|+c$

$-\frac{\cos ^4 x}{(1+\sin x)^3}+c$

$-\frac{\cos ^3 x}{(1+\sin x)^3}+c$

$-\frac{\cos ^4 x}{(1+\sin x)^4}+c$

$-\frac{\cos ^4 x}{4(1+\sin x)^4}+c$

$\frac{-3}{2}$

$\frac{-1}{2}$

2

$\frac{5}{2}$