1
WB JEE 2025
MCQ (Single Correct Answer)
+1
-0.25
Change Language

Consider a particle of mass 1 gm and charge 1.0 Coulomb is at rest. Now the particle is subjected to an electric field $E(t)=E_0 \sin \omega t$ in the $x$-direction, where $E_0=2$ Newton/Coulomb and $\omega=1000 \mathrm{rad} / \mathrm{sec}$. The maximum speed attained by the particle is

A
$2 \mathrm{~m} / \mathrm{sec}$
B
$4 \mathrm{~m} / \mathrm{sec}$
C
$6 \mathrm{~m} / \mathrm{sec}$
D
$8 \mathrm{~m} / \mathrm{sec}$
2
WB JEE 2025
MCQ (Single Correct Answer)
+1
-0.25
Change Language

Two charges $+q$ and $-q$ are placed at points $A$ and $B$ respectively which are at a distance $2 L_{\mathrm{p} p a t}$ $C$ is the mid point of $A$ and $B$. The workdone in moving a charge $+Q$ along the semicircle $\operatorname{CSD}\left(W_V\right)$ and along the line $\mathrm{CBD}\left(W_2\right)$ are

WB JEE 2025 Physics - Electrostatics Question 1 English

A
$\frac{q Q}{4 \pi \epsilon_0 L}, \frac{q Q}{4 \pi \epsilon_0 L}$
B
$\frac{-Q q}{6 \pi \epsilon_0 L}, \frac{-Q q}{6 \pi \epsilon_0 L}$
C
$\frac{-Q q}{6 \pi \epsilon_0 L}, \frac{-Q q}{12 \pi \epsilon_0 L}$
D
$\frac{q Q}{4 \pi \epsilon_0 L}, 0$
3
WB JEE 2024
MCQ (Single Correct Answer)
+1
-0.25
Change Language

A charge Q is placed at the centre of a cube of sides a. The total flux of electric field through the six surfaces of the cube is

A
$$ \frac{6 \mathrm{Qa}^2}{\epsilon_0} $$
B
$$ \frac{\mathrm{Q} \mathrm{a}^2}{6 \epsilon_0} $$
C
$$ \mathrm{Q} / \epsilon_0 $$
D
$$ \mathrm{Q} \mathrm{a}^2 / \epsilon_0 $$
4
WB JEE 2024
MCQ (Single Correct Answer)
+1
-0.25
Change Language

Three point charges $$\mathrm{q},-2 \mathrm{q}$$ and $$\mathrm{q}$$ are placed along $$x$$ axis at $$x=-{a}, 0$$ and $a$ respectively. As $$\mathrm{a} \rightarrow 0$$ and $$\mathrm{q} \rightarrow \infty$$ while $$\mathrm{q} \mathrm{a}^2=\mathrm{Q}$$ remains finite, the electric field at a point P, at a distance $$x(x \gg a)$$ from $$x=0$$ is $$\overrightarrow{\mathrm{E}}=\frac{\alpha \mathrm{Q}}{4 \pi \epsilon_0 x^\beta} \hat{i}$$. Then

A
$$\alpha=\beta$$
B
$$\alpha=2 \beta$$
C
$$\alpha=\frac{2}{3} \beta$$
D
$$2 \alpha=3 \beta$$
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