1
WB JEE 2022
+1
-0.25

Certain amount of an ideal gas is taken from its initial state 1 to final state 4 through the paths 1 $$\to$$ 2 $$\to$$ 3 $$\to$$ 4 as shown in figure. AB, CD, EF are all isotherms. If vp is the most probable speed of the molecules, then

A
vp at 3 = vp at 4 > vp at 2 > vp at 1
B
vp at 3 > vp at 1 > vp at 2 > vp at 4
C
vp at 3 > vp at 2 > vp at 4 > vp at 1
D
vp at 2 = vp at 3 > vp at 1 > vp at 4
2
WB JEE 2022
+1
-0.25

Consider a thermodynamic process where integral energy $$U = A{P^2}V$$ (A = constant). If the process is performed adiabatically, then

A
AP2(V + 1) = constant
B
(AP + 1)2V = constant
C
(AP + 1)V2 = constant
D
$${V \over {{{(AP + 1)}^2}}}$$ = constant
3
WB JEE 2022
+1
-0.25

One mole of a diatomic ideal gas undergoes a process shown in P-V diagram. The total heat given to the gas (ln 2 = 0.7) is

A
2.5 P0V0
B
3.9 P0V0
C
1.1 P0V0
D
1.4 P0V0
4
WB JEE 2022
+2
-0.5

One mole of an ideal monoatomic gas expands along the polytrope PV3 = constant from V1 to V2 at a constant pressure P1. The temperature during the process is such that molar specific heat $${C_V} = {{3R} \over 2}$$. The total heat absorbed during the process can be expressed as

A
$${P_1}{V_1}\left( {{{V_1^2} \over {V_2^2}} + 1} \right)$$
B
$${P_1}{V_1}\left( {{{V_1^2} \over {V_2^2}} - 1} \right)$$
C
$${P_1}{V_1}\left( {{{V_1^3} \over {V_2^2}} - 1} \right)$$
D
$${P_1}{V_1}\left( {{{V_1^{}} \over {V_2^2}} - 1} \right)$$
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